Andrew Bogut
Known for: NBA player for Milwaukee Bucks, Golden State Warriors, NBA Champion 2015, Australian National Team
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About Andrew Bogut's Height
Andrew Bogut, born November 28, 1984, in Melbourne, Australia, is a retired professional basketball player known for his defensive prowess and passing ability as a center. Drafted first overall in the 2005 NBA Draft by the Milwaukee Bucks, Bogut had a successful career with the Bucks, Golden State Warriors, Dallas Mavericks, and Cleveland Cavaliers. He won an NBA Championship with the Warriors in 2015 and was instrumental in their defensive schemes. Bogut also had a distinguished international career with the Australian national team and later played in the NBL for the Sydney Kings.
Andrew Bogut stands at 6'11.9" (213 cm), which is well above average for a male. This is 38.0 cm taller than the average height for men(5'8.9" (175 cm)).
Interesting Facts
- First Australian to be drafted first overall in the NBA.
- Won an NBA Championship with the Warriors.
- Played 14 seasons in the NBA.
- Known for his shot-blocking and passing from the center position.
- Active in Australian basketball media post-retirement.
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Andrew Bogut is 213 cm tall, which is approximately 6'12". Need to convert between different height units? Our height converter calculator makes it easy to convert between centimeters, feet, inches, and meters.
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