Jon Moxley Height

About Jon Moxley's Height

Jon Moxley, born Jonathan David Good on December 7, 1985 in Cincinnati, Ohio, is a renowned American professional wrestler best known for his intense persona and hardcore wrestling style. He first gained prominence under the ring name Dean Ambrose in WWE, where he was a key member of the iconic faction The Shield alongside Roman Reigns and Seth Rollins. During his WWE tenure from 2011 to 2019, Moxley captured multiple championships including the WWE Championship and three Intercontinental Championships. After departing WWE in April 2019 due to creative differences and a desire for greater artistic freedom, Good reinvented himself as Jon Moxley on the independent circuit and quickly became one of All Elite Wrestling’s (AEW) biggest stars. He debuted at AEW’s inaugural Double or Nothing event in May 2019 and, in February 2020, became AEW World Champion after defeating Chris Jericho. Moxley's career is marked by his willingness to compete in brutal matches across global promotions, including New Japan Pro-Wrestling, where he has held the IWGP United States Heavyweight Championship multiple times. Known for gritty promos and an unpredictable brawling style inspired by wrestling legends, Moxley is synonymous with modern hardcore wrestling. Outside the ring, he is the author of an acclaimed autobiography, 'MOX,' and is married to sports broadcaster Renee Paquette. His journey from the independence circuit to worldwide superstardom is a testament to his resilience and authenticity.

Jon Moxley stands at 6'2" (188 cm), which is above average for a male. This is 13.0 cm taller than the average height for men(5'8.9" (175 cm)).

Jon Moxley Interactive Height Comparison

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